2^2(42)+2x=20

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Solution for 2^2(42)+2x=20 equation: 



2^2(42)+2x=20

We move all terms to the left:

2^2(42)+2x-(20)=0

determiningTheFunctionDomain
2x-20+2^242=0

We add all the numbers together, and all the variables

2x+72+7.0673882591135E=0

We add all the numbers together, and all the variables

2x+91.211153079413=0

We move all terms containing x to the left, all other terms to the right

2x=-91.211153079413

x=-91.211153079413/2

x=-45+1/1.6513189240862

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